shawnpwilson
01-18-2005, 04:40 AM
Hello,
I was looking at the 8/8/8 Tutorial number 2 about hooking up an LED to a digital output. My question is this: Why isn't there a need for resistor to be placed before the LED so it doesn't burn out? On other IO boards cockpit builders use, to power a LED requires a resistor to restrict current so the LED doesn't burn out. Is there some internal circuitry in the 8/8/8 to protect a LED from burning out? Does the 0/16/16 act the same way?
Thank you.
Shawn
I was looking at the 8/8/8 Tutorial number 2 about hooking up an LED to a digital output. My question is this: Why isn't there a need for resistor to be placed before the LED so it doesn't burn out? On other IO boards cockpit builders use, to power a LED requires a resistor to restrict current so the LED doesn't burn out. Is there some internal circuitry in the 8/8/8 to protect a LED from burning out? Does the 0/16/16 act the same way?
Thank you.
Shawn